# Ex 9.6, 2 - Chapter 9 Class 12 Differential Equations (Term 2)

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Ex 9.6, 2 For each of the differential equation , find the general solution : 𝑑𝑦𝑑𝑥+3𝑦= 𝑒−2𝑥 𝑑𝑦𝑑𝑥+3𝑦= 𝑒−2𝑥 Step 1: Put in form 𝑑𝑦𝑑𝑥 + Py = Q 𝑑𝑦𝑑𝑥 + 3y = 𝑒−2𝑥 Step 2: Find P and Q by comparing, we get 𝑃=3 and Q = 𝑒−2𝑥 Step 3 : Find Integrating factor, I.F. I.F. = 𝑒 𝑝𝑑𝑥 I.F. = 𝑒 3𝑑𝑥 I.F. = 𝑒3𝑥 Step 4 : Solution of the equation y × I.F. = 𝑄×𝐼.𝐹. 𝑑𝑥+𝑐 Putting values y × e3x = 𝑒−2𝑥 + 3𝑥 ,dx + 𝑐 ye3x = 𝑒𝑥 dx + 𝑐 ye3x = 𝑒𝑥 dx + 𝑐 Dividing by 𝑒3𝑥 y = e–2x + Ce–3x

Ex 9.6

Ex 9.6, 1
Important

Ex 9.6, 2 You are here

Ex 9.6, 3 Important

Ex 9.6, 4

Ex 9.6, 5 Important

Ex 9.6, 6

Ex 9.6, 7 Important

Ex 9.6, 8 Important

Ex 9.6, 9

Ex 9.6, 10 Deleted for CBSE Board 2022 Exams

Ex 9.6, 11 Deleted for CBSE Board 2022 Exams

Ex 9.6, 12 Important Deleted for CBSE Board 2022 Exams

Ex 9.6, 13

Ex 9.6, 14 Important

Ex 9.6, 15

Ex 9.6, 16 Important

Ex 9.6, 17 Important

Ex 9.6, 18 (MCQ)

Ex 9.6, 19 (MCQ) Important Deleted for CBSE Board 2022 Exams

Chapter 9 Class 12 Differential Equations (Term 2)

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.